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shyam

· started a discussion

· 1 Months ago

short (Question: 257143.0 )

in triangle AOB.....90-A/2 = 40 degree is the answer

Question:

In given figure, O is the centre of circle ∠AQB = 100°, ∠APB = 60°, then find ∠AOB.

  

Options:
A)

30°

B)

40°

C)

60°

D)

80°

Solution:

Ans: (b)

  

As angle in same segment are equal , therefore angle AOB= 40 degree

manoj kumar

· commented

· 1 Months ago

as i know this theory applicable in internal angle bisector but here not mentioned aq & bq are angle bisector so how can we use it here.......................
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