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Pradeep Kumar

· started a discussion

· 1 Months ago

Right Question (Question: 246297.0 )

They are asking the remainder not the value.

8641+8642+........+8650= 8640(1+2+....+10)= 8640*55

when we divide this with 8640 then it will be completely divisible and remainder will be zero.

Question:
Find the remainder when the product of 10 consecutive natural numbers starting from 8641 is divided by 8640.
Options:
A) 3
B) 8639
C) 0
D) 55
Solution:

Ans: (c)

Required Remainder 


Sahil

· commented

· 1 Months ago

Bhai its given product in between, not addition so answer is right. I also did the same mistake
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