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Ravi Raj Meena

· started a discussion

· 1 Months ago

RIGHT ANSWER (Question: 108114.0 )

The area of the square is 324, hence its side is 18 cm.
Volume of the pyramid = 1/3 * Area of the base * Height.
1296 = 1/3 * 324 * Height.
So Height = 12 cm.
Slant Height of the pyramid with square base = √ (h^2 + a^2/4) = √(12^2 + 18^2/4)
Slant Height = 15cm
Area of the lateral face = 1/2 * Base * Height = 1/2 * 18 * 15 = 135 cm^2.
Pyramid with a square base has 4 lateral faces, so lateral surface area of the pyramid = 4 * 135 = 540 cm^2

Question:

Base of a right pyramid is a square of area 324 sqm. If the volume of the pyramid is 1296 cu.m., then the area (in m2) of the slant surface is:

Options:
A) 360
B) 432
C) 540
D) 1080
Solution:
Ans: (c)

Height of pyramid = \(\cfrac{1296}{324}\times3=12\) mtr.

Slant height = \(\sqrt{12^2+9^2}=15\)     [\(\because\)Side of square = 18 m]

Area of slant surface  = \(4\times\cfrac{1}{2}18\times1515=540\) m2

Knowledge Expert

· commented

· 1 Months ago

Given answer is correct: area of triangle is: 1/2 x b x h

ANKITA

· commented

· 1 Months ago

thnx ravi

Sudesh Kumar

· commented

· 1 Months ago

thanku

Suresh Kumar

· commented

· 1 Months ago

thnk u

Mahesh Reddy

· commented

· 1 Months ago

thanx
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