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sunil chaudhary

· started a discussion

· 1 Months ago

reply (Question: 111642.0 )

please mention your question

Question:

D, E, F are the mid-points of BC, CA, AB of triangle ABC. If AD and BE intersect in G, then AG + BG + CG is equal to:

Options:
A) AD = BE = CF
B) \(\cfrac{2}{3}\)(AD + BE + CF)
C) \(\cfrac{3}{2}\)(AD + BE + CF)
D) \(\cfrac{1}{3}\)(AD + BE + CF)
Solution:
Ans: (b)

Since G is the centroid of \(\triangle\)ABC


Hence, AG + BG+ CG = \(\cfrac{2}{3}\) (AD + BE + CF)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Please elaborate your query and we will solve it.

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