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Thulasi Ram

· started a discussion

· 1 Months ago

Ram (Question: 186117.0 )

Practically a^6+1 cannot be equal to zero.

Question:
If a + \(\cfrac{1}{a}\)  = \(\sqrt{3}\), then the value of a18 + a12 + a6 + 1 is –
Options:
A) 0
B) 1
C) -1
D) 4
Solution:
Ans: (a)  

a18 + a12 + a6  + 1 

= a12 (a6 +1) + 1 (a6 + 1)

\(\therefore \)  

=  (a12 + 1) (a6 +1) 

= (a12 + 1) × 0 = 0 

GAURAV RAWAT

· commented

· 1 Months ago

good point .....y not answered
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