CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Rahul Goyal

· started a discussion

· 1 Months ago

qustion 52 (Question:605594.0)

vedio solution

Question:
Find the equation of the line passing through the intersection of the lines 3x + 4y = 7 and x – y + 2 = 0 and having slope 3.
Options:
A) 12x + 15y + 18 = 0
B) 14x + 11y + 23 = 0
C) 15x + 7y + 9 = 0
D) 21x – 7y + 16 = 0
Solution:
Ans:(d) The equation of line passing through the intersection of lines 3x + 4y = 7 and x – y + 2 = 0 is:

(3x + 4y – 7) + k (x – y + 2) = 0

3x + 4y – 7 + k x – ky + 2k = 0

(3 + k)x + (4 – k)y – 7 + 2k = 0

Slope of line = \(-\cfrac{(3+k)}{4-k}\) = 3

⇒ – (3 + k) = 3 (4 – k)

⇒ – (3 – k) = 12 – 3k

⇒ 2k = 15 ⇒ k = \(\cfrac{15}{2}\)

∴ Required equation of the line is:

(3x + 4y – 7) + \(\cfrac{15}{2}\) (x – y + 2) = 0

2(3x + 4y – 7) + 15(x – y + 2) = 0

⇒ 6x + 8y – 14 + 15x – 15y + 30 = 0

⇒ 21x – 7y + 16 = 0

Knowledge Expert

· commented

· 1 Months ago

Dear student, Currently it is not available but we will look towards your issue. thanks for showing your interest. Keep learning, Team TR
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions