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Anusuri Bhargava

· started a discussion

· 1 Months ago

bro plese correct question the avg of xyz is not given

Question:
The average of three numbers x, y and z is 45. x is greater than the average of y and z by 9. The average of y and z is greater than y by 2.Then the difference of x and z is?
Options:
A) 3
B) 5
C) 7
D) 11
Solution:
x+y+z=3\(\times\)45=135...........(i)

x=(y+z)/2+9

2x -y-z=18....................(ii)

and (y+z)/2=y+2

y+z=2y+4

z-y=4.......................(iii)

from equation (i) and (ii)

3x=135+18=153

x=51

from equation (i) and (iii)

x+y+z+z-y=135+4=139

x+2z=139

51+2z=139

2z=88

z=44

x-z=51-44=7

Knowledge Expert

· commented

· 1 Months ago

Dear student
We resolved it.

Best wishes
Team TR

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