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sachin

· started a discussion

· 1 Months ago

question mistake (Question: 470923.0 )

area BEA : AREA ADC

Question:

In a ∆ABC, D is the midpoint of line BC and E is the mid-point of AD. Then find the ratio of area of ∆BEA and ∆ADC. 

Options:
A)

1 : 2

B)

1 : 4

C)

1 : 3

D)

1 : 6

Solution:

Ans: (a)

  

Let the area of ∆ABC = X units 

AD is median, 

Then,

Area of  ∆ABD =  12    × area of  ∆ABC

=  12     × x =  x2    units 

E is midpoint of AD,

  

So,

BE is median.

Area of ∆BED = Area of ∆ BEA =  12    × ABD  

Area of ∆BEA =  12    ×  x2     =  x4     units  

Area of ∆BEA : Area of ∆ADC =  x4      :  x2    

= 1 : 2 

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Please be specific and clear in asking your doubt.

Best wishes
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