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Purnasha Rudra

· started a discussion

· 1 Months ago

Question is ambiguous. (Question: 107798.0 )

Taking one side as the longest median of triangle ABC, the other two sides can have many values because of which the area of the triangle will be different for different values of the other sides.

Question:

The semi-perimeter of a right angled triangle ABC is 12 cm and the shortest median is 5 cm. What is area of the triangle which has the largest median of triangle ABC as its longest side?

Options:
A) \(\sqrt[]{73}\) cm2  
B) 10 cm2
C) 12 cm2  
D) None of these
Solution:
Ans: (c) 


Given: S = 12 cm & BP = 5 cm

∴ AP = PC = BP = 5 cm

∴ AC = 10 cm

 We know the ratio of Right triangle like (3:4:5) 

      then we assume the ratio, (6:8:10)

So, the other two sides = 8 cm, 6 cm

∴ Area of ∆QBC = \(\cfrac{1}{2}\times\) QB × BC = \(\cfrac{1}{2}\times\) 4 × 6 = 12 cm2

Knowledge Expert

· commented

· 1 Months ago

Dear student Solution is already in detail. Please try again Best wishes Team TR
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