. (Question:338260.0)

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Kumar

· started a discussion

· 1 Months ago

This topic is not avialable

shruti

· started a discussion

· 1 Months ago

? (Question: 338260.0 )

whole solution you gave is assumption based.. but please let us know on what is the assumption based?

Amar Chandra kumar

· started a discussion

· 1 Months ago

@ (Question: 338260.0 )

I gonna KD CMPS... ridiculous questions here

Question:

Two people, A and B, need to cross a bridge. A can cross the bridge in 10 minutes and B can cross in 5 minutes. There is also a bicycle available and any person can cross the bridge in 1 minute with the bicycle. Then the shortest time that both men can get across the bridge is nearest to:

Options:

7.23 minutes

3.77 minutes

2.72 minutes

2.12 minutes

Solution:

suppose speed of A is 1 m/min and B = 2 m/minthen length of bridge = 10m and also speed of them with bicycle is 10 m/minFirst A will go by cycle and left it in the middle then he will go on foot and meanwhile B will catch the cycle and reach the other end of the bridge, they both will reach together.suppose A goes x m by cycleSo, $\frac{x}{10}$ + $\frac{10 - x}{1}$ = $\frac{x}{2}$ + $\frac{10 - x}{10}$ = total time=> x + 100 - 10x = 5x + 10 - x=> 13x = 90=> x = 90/13putting x = 90/13 in $\frac{x}{10}$ + $\frac{10 - x}{1}$ => $\frac{90}{130}$ + $\frac{10 - \frac{90}{13}}{1}$ => $\frac{90 + 1300 - 900}{130}$ => 49/13=> 3.769xxx => 3.77 min

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