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girdhari

· started a discussion

· 1 Months ago

.... (Question: 293506.0 )

Solution: The spherical ball will have a surface area equal to 4πr2. The outer surface area of each of the smaller solid part will be 4πr2/8 ➾ πr2/2 and the inner part, which will look like one eighth of an orange will be quarter of a circle on left side, quarter of a circle on the right side and a quarter of a circle at the bottom as well. Opening it up you will get this as three-fourth of a complete circle. Thus this one piece will have a surface area equal to (πr2/2) + (πr2 × ¾). The total of this part will be 5/4πr2. This is what fraction of the original surface area i.e. 4πr2. This will give the ratio as 5/16. Thus 3rd option is the answer.

Question:

A solid spherical ball is cut into eight identical pieces by three mutually orthogonal planes. The proportion the area of any of these pieces bears to the area of the uncut solid spherical ball is –

Options:
A)

913    

B)

1116    

C)

516    

D)

None of these

Solution:

Ans: (c)

  

Mahesh Sandeboina

· commented

· 1 Months ago

thanx brother

Gurdeep Kaur

· commented

· 1 Months ago

thankyou so much for the amazing job , had you not explained it i would not have understand their solution.
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