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Ankit Malik

· started a discussion

· 1 Months ago

? (Question: 274656.0 )

11+11+(1*1) = 23 not 145

Question:

Let ‘M’ be a two-digit number and ‘N’ be another two digit number formed by reversing the digits of M. If M + N + (Product of digits of number M) = 145 then what is the sum of the digits of M?

Options:
A)

9

B)

10

C)

11

D)

12

Solution:

Ans: (c)

Let one’s place = x

Ten’s place = y

Number = 10y + x = M

N = 10x + y

M + N = 11y + 11x = 11(y + x)

11(y + x) + xy = 145

Now, use options.

(a)    x + y = 9

11 × 9 + xy = 145

xy = 46

Required factors not possible.

(b)    x + y = 10

xy = 35

It has only 5; 7 are factors.

Not possible

(c)    x + y = 11

xy = 24

3 × 8 = 24, 3 + 8 = 11

So, answer is 11.

Knowledge Expert

· commented

· 1 Months ago

@Ankit Malik


It ok. no issue.

Best wishes
Team Toprankers

Ankit Malik

· commented

· 1 Months ago

soorry
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