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· 1 Months ago

Question:
If (a- 1)2 + (b+2)2 +(c+ 1)2 = 0, then the value of 2a - 3b + 7c is:
Options:
A) 12 
B) 3
C) -11 
D) 1
Solution:

(a- 1)2 + (b+2)2 +(c+ 1)2 = 0

⇒ a – 1 = 0 ⇒ a = 1;

b + 2 = 0 ⇒ b = -2

c + 1 = 0 ⇒ c = -1

∴ 2a – 3b + 7c

= 2 – 3(-2) + 7(- 1) = 2 + 6 – 7 = 1

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