CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Sanjukta

· started a discussion

· 1 Months ago

(Question:111617.0)

Question:

If 2 sin2x + cos2 45° = tan 45°, where 0 < x < 90°, then x=?

Options:
A)

90° 

B) 60° 
C) 30° 
D) 45° 
Solution:
Ans: (c)

2 sin2 x + cos2 45° =  tan 45°

or \(2sin^2x+\left ( \cfrac {1}{\sqrt{2}} \right )^2=1\)

or 2sin2x + \(\cfrac{1}{2}=1\)

or sin2x= \(\cfrac{1}{4}\)

\(\therefore \ sin\ x=\cfrac{1}{2}=sin 30^o\)               \((\because \ 0 \leq x \leq 90^o)\)

\(\therefore\) x = 30°


Knowledge Expert

· commented

· 1 Months ago

Dear student
Please specify your doubt clearly in case of any ambiguity .

Keep learning
Team T
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions