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ruma

· started a discussion

· 1 Months ago

? (Question: 107567.0 )

wrong question?

Question:

The ratio of water and alcohol in two different containers is 2 : 3 and 4 : 5. In what ratio we are required to mix the mixtures of two containers in order to get the new mixture in which the ratio of alcohol and water be 7 : 5?

Options:
A) 7 : 3  
B) 5 : 3
C) 8 : 5 
D) 2 : 7
Solution:

Ans: (b) Let mixtures are mixed in x : y


\(\cfrac{18x + 20y}{27x + 25y}\ \ = \cfrac{5}{7}\)

126x + 140y = 135x + 125y

9x = 15y

\(\cfrac{x}{y} = \cfrac{15}{9} = \cfrac{5}{3}\)


Alternate sol:



Knowledge Expert

· commented

· 1 Months ago

Question is correct........solve it properly........
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