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Anugrah Kumar

· started a discussion

· 1 Months ago

questio (Question:97907.0)

0kp

Question:
In an arithmetic progression, the first and the last terms are 9 and 96 respectively. If the sum of all the terms of the progression is 4200, what is the common difference?
Options:
A) 80
B) \(\cfrac{76}{79}\)
C) 70
D) \(\cfrac{87}{79}\)
Solution:

Ans: (d) Let the number of terms in the arithmetic progression be n.

\(\cfrac{n}{2}\) [9 + 96] = 4200 ⇒ n = 80.

96 = 9 + (n - 1) d = 9 + 79d

d = \(\cfrac{87}{79}\) .

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct, kindly write your query specifically
.
Regards
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