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Aamit Kumar

· started a discussion

· 1 Months ago

ques tion is misprint (Question: 231146.0 )

ok thanks qno 2

Question:
A student multiplied a number by \(\cfrac{3}{5}\)instead of \(\cfrac{5}{3}\) . What is the percentage error in the calculation?
Options:
A) 44%
B) 34%
C) 54%
D) 64%
Solution:
Let the number = x

According to the question

wrong answer = \(\cfrac{3}{5}x\)

correct answer= \(\cfrac{5}{3}x\)

Required percent error  

\(\cfrac{\cfrac{5}{3}x-\cfrac{3}{5}x}{\cfrac{5}{3}x}\times100=\cfrac{16x}{15}\times\cfrac{3}{5x}\times100\)

Required percent error =64% 

Knowledge Expert

· commented

· 1 Months ago

We made the required correction.
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