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chandranshu

· started a discussion

· 1 Months ago

querry (Question: 115785.0 )

p and q are centre so answer should be 7

Question:
In the adjoining figure, ACB is a right angled triangle. CD is the altitude. Circles are inscribed within the triangles ACD, BCD. P and Q are the centres of the circles. The distance PQ is (approx) :  

Options:
A) 5
B) \(\sqrt[]{50}\)
C) 7
D) 8
Solution:
Ans: (b)


chandranshu

· commented

· 1 Months ago

radius of 1st circle is 4 and 2nd is 3 adding them will get 7
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