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Jaya

· started a discussion

· 1 Months ago

Quant (Question: 110238.0 )

Iska answer 3 option aa rha h. Please tell me

Question:

The value of sin θ + sin (θ + 120°) + sin (θ + 240°) is equal to:

Options:
A) 0
B) 1
C) \(\sqrt[]{3}\)
D) 2
Solution:
Ans: (a) The given expression is

sinθ + sin (θ+120°) + sin (θ+240°)


= sinθ + \(\left [sin \left (\theta + \cfrac {2\pi}{3} \right )+sin\left ( \theta+\cfrac {4\pi}{3} \right ) \right ]\)

= sinθ  + 2 sin (θ + \(\pi\)) cos \(\cfrac{\pi}{3}\)

\(\left [ \therefore sin \ C + sin\ D = 2sin \cfrac{C+ D}{2} cos \cfrac{C-D}{2}\right ]\)

= sinθ  + sin (\(\pi\) + θ)

= sinθ - sinθ

= 0

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
The given answer is correct.
Solution is also given and is correct.

Thanks and Regards
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