Q149 (Question:497808.0)

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Him Sagar Ons

· started a discussion

· 1 Months ago

Q149 (Question:497808.0)

sir 9 do bar kyon liye

Question:

Find the total number of 8 digits numbers that can be formed, all having different digits.

Options:

9 × 9!

9 × 8!

$\frac{9}{2} \times 9!$

$\frac{9}{2} \times 8!$

Solution:

Ans: (c)

Required number of arrangements

= 9 × 9 × 8 × 7 × 6 × 5 × 4 × 3

= $9 \times \frac{9!}{2}$

= $\frac{9}{2} \times 9!$

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Q149 (Question:497808.0)

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