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GAURAV KUMAR

· started a discussion

· 1 Months ago

Q (Question: 286823.0 )

5 sec ka he sol h ...

TAN 30°=r/3

Question:

A circle is inscribed in a triangle ABC. It touches side AB at point p. If  ∠A = 60°, AX = 3 cm, BX = 5 cm, then find the radius of circle ?

Options:
A)

357    

B)

573    

C)

5173    

D)

3    

Solution:

Ans: (d)

  

GAURAV KUMAR

· commented

· 1 Months ago

SRY
FIRST IN TRIANGLE APQ
AP=AQ

THEN IN TRIANGLE AOQ
......

GAURAV KUMAR

· commented

· 1 Months ago

Let O is center of circle.
In Triangle AOQ

(AP=AQ).
SO Angle (OAP) =Angle (OAQ)=60°/2
TAN(OAQ°) = r/3
TAN 30°=r/3

dhruva tripathi

· commented

· 1 Months ago

kindly explain this method???

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

yes this one also an approach to find answer, here we illustrate its detailed explanation.

Keep learning Keep solving
Best wishes
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