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GAURAV KUMAR

· started a discussion

· 1 Months ago

Q (Question: 193706.0 )

LAST TERM SHOULD BE
(SIN 69°)^2

Question:
The value of \(\cfrac{sin39^0}{cos51^0} \)  + 2 tan11º. tan31º. tan45º. tan59º.tan79º – 3 (sin2 21º + sin269º) is:
Options:
A) 2
B) 1
C) -1
D) 0
Solution:
Ans: (d) 

   

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