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Ram Pravesh Mourya

· started a discussion

· 1 Months ago

Q.I.D--246875 (Question: 246875.0 )

25/X2=16/x2--16
I couldn't understand this step. Please discuss it.

Question:
PQ is a chord of length 8 cm of a circle with centre O and of radius 5 cm. The tangents at P and Q intersect at a point T. The length of TQ is –
Options:
A) \(\cfrac{15}{4}\)
B) \(\cfrac{10}{3}\)
C) \(\cfrac{20}{3}\)
D) \(\cfrac{21}{4}\)
Solution:
Ans: (c)


Avnish Pal Singh

· commented

· 1 Months ago

Triangle ORQ and OQT are similar thus QT/RQ = OR/OQ solve it.

devi thotada

· commented

· 1 Months ago

Triangles OQT and QRT are similar triangles because in both triangles R and Q are 90 degrees and have a common side QT,so we can write OQ^2/QR^2=QT^2/RT^2, OQ is radius,RQ is half of chord lenght and if QT is x then RT=X^2-16(since QRT is a right angle triangle)
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