q 7 (Question: 279530.0 )

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Ashish Pandey

· started a discussion

· 1 Months ago

q 7 (Question: 279530.0 )

how can you equate, OG & EF, since it is not given that the two chords are equidistant?neither the triangles OEG& OEF are similar.

Question:

Two chords of a circle, of lengths 2m and 2n are mutually perpendicular. If the distance of the point, at which the chords interest, from the centre of the circle is p, then the radius of the circle is-

Options:

m + n – p

$\sqrt{\frac{m^{2} - n^{2} - p^{2}}{2}}$

$\sqrt{\frac{m^{2} + n^{2} + p^{2}}{2}}$

$\sqrt{\frac{m n}{p}}$

Solution:

Ans: (c)

Anurag

· commented

· 1 Months ago

g & f are middle point of chord. so og &of are perpendicular on chords

Vikram Singh

· commented

· 1 Months ago

Yet to be approved!

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q 7 (Question: 279530.0 )

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