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Arbab Mahtab

· started a discussion

· 1 Months ago

Answer should be 50 A . You can refer J.B. Gupta for power system also.

Question:

If the fault current is 2000 Amp, the relay setting at 50% and CT ratio is  4005 , then the plug setting multiplier will be-

Options:
A)

25 Amp

B)

15 Amp

C)

50 Amp

D)

None of the above

Solution:

Ans:(d)

Fault current = 2000 amp

CT Ratio =  4005    

rated CT current for relay = 5amps

Relay setting = 50%

\(\therefore\) Pick up current for relay = 50% of 5 

= 2.5 amp.

\(\therefore\) fault current at secondary of CT 

=   5400  × 2000 = 25Amp

Plug Setting multiplier =  252.5 = 10 

Kartik Khunger

· commented

· 1 Months ago

then u explain please

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