provide full solution (Question:620660.0)

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Adi Mishra

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· 1 Months ago

provide full solution (Question:620660.0)

ans is not coming

Question:

If x = $\frac{2 a b}{b^{2} + 1}$ then value of $\frac{\sqrt{a + x} + \sqrt{a - x}}{\sqrt{a + x} - \sqrt{a - x}}$ is-

Options:

a + b

a – b

Solution:

Ans: (d)

a + x = a + $\frac{2 a b}{b^{2} + 1}$

= $\frac{a (b^{2} + 1) + 2 a b}{b^{2} + 1}$

= $\frac{a (b^{2} + 1 + 2 a b)}{b^{2} + 1}$ = $\frac{a {(b + 1)}^{2}}{b^{2} + 1}$

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provide full solution (Question:620660.0)

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