Provide answer (Question:275988.0)

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Provide answer (Question:275988.0)

I cant understand

Question:

In the given figure। ABC is a triangle in which, AB=12cm, AC= 6cm and altitude AD=4 cm. If AE is the diameter of the circle, then what is the length (in cm) of circum-radius?

Options:

Solution:

$\begin{matrix} A B = 12 c m, A C = 6 c m, A D = 4 c m \\ J o i n E C \\ ∠ A B D = ∠ A E C (angle made by same arc AC) \\ Δ A B D ~ Δ A E C (By AA similarity) \\ \frac{AB}{AE} = \frac{AD}{AC} \\ \frac{12}{AE} = \frac{4}{6} \\ A E = 18 c m \\ C i r c u m r a d i u s = \frac{AE}{2} = \frac{18}{2} = 9cm \end{matrix}$

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