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Vijay Sharma

· started a discussion

· 1 Months ago

POOR SOLUTION (Question: 108514.0 )

PLEASE PROVIDE SOME GOOD SOLUTION TO THIS

Question:

A fruit-vendor purchases some oranges at the rate of 6 in Rs.1 and again he purchased same number of oranges at the rate of 4 in Rs.1. He mixes them and sells both type of oranges at the rate of 10 in Rs.2. If he got a loss Rs.4 in the total transaction, then find the total number of oranges that he bought.

Options:
A) 480
B) 840
C) 490
D) Data inadequate
Solution:
Ans: (a)

The number of Ist type oranges bought by fruit-vendor = x

Then, the number of IInd type oranges bought by fruit-vendor = x

\(\therefore\)Total number of oranges bought = x + x = 2x

Now, total C.P. = \(\cfrac{x}{6}+\cfrac{x}{4}=\cfrac{5x}{12}\)

\(\therefore\) Total S.P. = \(2x\ \times \cfrac{2}{10}=\cfrac{2x}{5}\)

A.T.Q., 

\(\cfrac{5x}{12}-\cfrac{2x}{5}=4\Rightarrow \cfrac{25x-24x}{60} =4\Rightarrow x = 240 \) x = 240

\(\therefore \) Total number of oranges bought = 240 × 2 = 480

ATUL KUMAR SINGH

· commented

· 1 Months ago

use of lcm method..

Sohil Rajput

· commented

· 1 Months ago

isse acha kya solution hoga akal ke andhe
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