Discussions
Select Date
Tags:
MANISH VAISHNAV

· started a discussion

· 1 Months ago

Any short trick related these type questions

Question:
An equilateral triangle circumscribes all the six circles, each with radius 1 cm. What is the perimeter of the equilateral triangle?

Options:
A) 6(2+\(\sqrt{3}\)) cm
B) 3(\(\sqrt{3}\) + 2)  cm
C) 12(\(\sqrt{3}\)+4) cm
D) None of the above
Solution:
Ans: (a) 


DE = GH = 4, \(\angle \)ADG = 60°

Then from 30 - 60 - 90 theorem

AG = \(\sqrt[]{3},\ BH\ = \sqrt[]{3},\) then

AB = AG+GH+BH

Then perimeter of \(\triangle\)ABC = \(3\times \left ( \sqrt[]{3}+4+\sqrt[]{3} \right )=3\times \left ( 2\sqrt[]{3}+4 \right )=6\left ( \sqrt[]{3}+2 \right )\)

Knowledge Expert

· commented

· 1 Months ago

Dear student, solution is appropriate according to the question. Keep learning, Team TR

All Rights Reserved Top Rankers