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shavy

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· 1 Months ago

plzz give solution (Question: 113543.0 )

solution.......????????????????????????????

Question:

In an examination the standard of passing was 40%. Out of 9 students who appeared, 4 failed and the remaining get 80%, 57%, 51%, 68% and 79% marks. The median of the percentage marks is equal to:

Options:
A) 51%
B) 57%
C) 68%
D) 79%
Solution:
Ans: (a) From question: 

we can say that the students who failed are below 40% mark's students. So Arranging their percentage marks in increasing order 

F1 F2 F3 F4 51% 57% 68% 79% 80% 

\(\therefore\) median of the % marks = \(\cfrac{n + 1}{2}\) th students marks 

= \(\cfrac{9 + 1}{2}\) th students marks 

= 5th student's marks 

i.e. 51%. 

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