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Utkarsh Sharma

· started a discussion

· 1 Months ago

plz explain 2nd line (Question: 108574.0 )

plz explain 2nd line

Question:

OD, OE and OF are perpendiculars drawn on the sides BC, AC and AB  from the internal point ‘O’ of an equilateral triangle ABC. If the lengths of these 

perpendiculars are 24, 20 and 22cm, then find the area of triangle ABC?



Options:
A) \(\cfrac{452}{\sqrt[]{3}}\) cm2
B) 351 cm2
C) 1452\(\sqrt[]{3}\) cm2
D) 927 cm2
Solution:
Ans: (c)

Let ‘a’ be the side of an equilateral triangle, then 

Area of triangle ABC = \(\cfrac{\sqrt{3}}{4}a^2\) 

Area of \(\Delta\)BOC + Area of \(\Delta\)COA + Area of \(\Delta\)AOB =

\(\cfrac{1}{2}a[24+20+22]\)

\(\therefore\) Area of equilateral triangle=cm


Ajeet

· commented

· 1 Months ago

Yet to be approved!

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
In 2nd line we have calculated area of triangle ABC by using area of equilateral triangle.
In next step we calculated area of BOC + COA + AOB which is also equal to area of ABC
Therefore in next step we have compared both areas.

Thanks and Regards
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