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Rajat Sharma

· started a discussion

· 1 Months ago

pls provide solution (Question: 246945.0 )

Somebody please provide detailed solution of this problem....

Question:
Find the area of the equilateral triangle inscribed in a circle circumscribed by a square made by joining the mid points of the adjacent sides of a square of side 8 cm. 
Options:
A) 12 cm2
B) \(12\sqrt{3}\) cm2
C) \(47(\pi-12)\) cm2
D) \(6\sqrt{3}\) cm2
Solution:
Ans: (d)


ANKIT

· commented

· 1 Months ago

given, length of larger square=8cm
now length of smaller sq formed by joining the midpoints of the larger sq=4*(2^1/2)=A(say)
radius of circle=A/2=circumradius of equilateral triangle.
so A=(side of triangle)/(3^1/2)
from here get side of tri. and use formula to find its area.
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