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SACHIN SAURAV

· started a discussion

· 1 Months ago

pls explain somebody (Question: 186072.0 )

how is this question done ?

Question:
Each edge of a regular tetrahedron is 4 cm. Its volume (in cubic cm) is –
Options:
A) \(\cfrac{16 \sqrt{3}}{3}\) cm3
B) 16 \(\sqrt{3}\) cm3 
C) \(\cfrac{16 \sqrt{2}}{3}\) cm3
D) 16 \(\sqrt{2}\) cm3
Solution:
Ans: (c) 

volume  of the regular tetrahedron

= \({\sqrt{2} \over 12}\)a3 

= \(\frac{\sqrt{2}}{12}\) × 4 × 4 × 4cm3 

= \(\cfrac{16 \sqrt{2}}{3}\)  cm3 

jayant upmanyu

· commented

· 1 Months ago

Yet to be approved!

jayant upmanyu

· commented

· 1 Months ago

Yet to be approved!

Knowledge Expert

· commented

· 1 Months ago

Volume of tetrahedron =√2/12 (side)^3=√2/12 (4)^3
=(√2 × 4 × 4 × 4)/12=(16√2)/3 cm^3
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