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mandeep jawla

· started a discussion

· 1 Months ago

pls explain (Question: 206624.0 )

how you calculated length out of hcf of areas of faces and base.
faces include all four walls of cuboid.. right?

Question:
The area of the base of a cuboidal box is 21 sq. cm and the area of the faces is 30 sq. cm. The numerical value of each of the dimensions of the box is an integer greater  than 1. Then the volume of the cuboidal box (in cu. cm) is –
Options:
A) 120
B) 105
C) 210
D) 630
Solution:
Ans: (c) Area of base = 21 sq. cm

             Area of faces = 30 sq. cm

                So, length = HCF of (area of base & area of faces) 

                                = 3 cm

So, volume of cuboidal box = \(\cfrac{21 × 30}{3}\)

= 210 cm3  


Alternate solution:

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