CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
DINESH BABU

· started a discussion

· 1 Months ago

pls clarify (Question: 186056.0 )

cant understand first step.,i think it must be 12.4(x+5)+26/(x+5)=12(x+5) ans :80

Question:
A man whose bowling average is 12.4, takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number of wickets taken by him before his last match is?
Options:
A) 64
B) 72
C) 80
D) 85
Solution:
Ans: (d) Let He has taken x wickets before the match.

And runs given with the average 12.4, So total run given was,

= 12.4x
Runs given including this match,

12.4x+26 with the average of 12.

Now,
(12.4x+26)/(x+5) = 12
12.4x+ 26 = 12x + 60
0.4x= 34
x = 85 wickets

Knowledge Expert

· commented

· 1 Months ago

Dear student,

Check 2 more methods to solve this question:

Short Solution:
If wickets taken till last match=x, then total runs upto last match=12.4x
So (12.4x+26)/(x+5)=12.4-0.4=12
On solving, x=85

Long Solution:
Let He has taken X wickets before the match.
And runs given with the average 12.4, So total run given was,
= 12.4X
Runs given including this match,
12.4X +26 with the average of 12.
Now,
(12.4X+26)/(X+5) = 12
12.4X + 26 = 12X + 60
0.4X = 34
X = 85 wickets

We wish you all the best.

Team Topranker
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions