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Sonu Kumar

· started a discussion

· 1 Months ago

that the 1st point is 1 and 5. It seems L and 5.

Question:

 If the point A(1, 5) , B(k, 1) and C(4, 11) are collinear, then find the value of k = ?


Options:
A)

     1

B)

     - 1

C)

     0

D)

     5

Solution:

  

For points to be collinear,  area of the triangle = 0

   =  12 [x1y2-y3+x2y3-y1+x3(y1-y2)]    

   12 [11-11+K11-5+4(5-1)]   

0 =  12 [-10+6k+16]   

    6 k + 6 = 0

     k = –1

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