CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Ambarish Gupta

· started a discussion

· 1 Months ago

please try to adhere to your promise (Question: 273472.0 )

please don't make such mistakes..this does nothing except wasting time and demotivating an aspirant...solution has been provided taking 4 holes while in question 2 holes are given..

Question:

A rectangular field is 22 m long and 10 m wide. Two hemispherical pit holes of radius 2 m are dug at two places and the mud is spread over the remaining part of the field. The rise in the level of the field is –

Options:
A)

893    m

B)

\(\frac{16}{93}\)  m

C)

\(\frac{352}{177}\)   m

D)

2393    m

Solution:

 

yogendra mishra

· commented

· 1 Months ago

surface area of 1 half spherical 2 .22/7 . r^2 so 2holes will be 2*.....
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions