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Beast

· started a discussion

· 1 Months ago

Please tell some alternate way to solve it (Question:134513.0)

Please tell some alternate way to solve it

Question:
The average monthly income of A and B is \(\unicode{x20B9} \)7760. The average monthly income of B and C is \(\unicode{x20B9} \)10990 and that of C and A is \(\unicode{x20B9} \)9070. What is the annual income of B? 
Options:
A) \(\unicode{x20B9} \)120240
B) \(\unicode{x20B9} \)124480
C) \(\unicode{x20B9} \)112360 
D) \(\unicode{x20B9} \)116160
Solution:

Total income of A and B = 2 x 7760

\(\Rightarrow\)A+B = 15520      ...(i) 

Similarly,

B +C = 10990\(\times\)2 =21980...(ii) 

and A+C = 9070 x 2 = 18140 ...(iii) 

Adding Eqs. (i), (ii) and (iii),

2(A + B + C) = 55640

⇒A+B + C =27820                   ,..(iv) 

Subtracting Eq. (iii) from Eq. (iv),

B = 27820 – 18140 = 9680 

Hence, annual income of

B = 9680 × 12 = \(\unicode{x20B9} \)116160

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is appropriate and basic,please solve it again.

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