Online Courses
Explore
Offline Courses
-
LAW
-
Judiciary
-
Management UG
-
CAT & OMETs
-
CUET
-
Design
-
Architecture
-
UPSC Law Optional
Explore
Test Series
Explore
Resources
-
LAW UG (5 Year LLB)
-
LAW UG (3 Year LLB)
-
LLM + LAW Officer
-
Judiciary
-
Management UG
-
Management PG
-
Design & Arch.
-
NTA CUET [UG]
-
Career Counselling
-
Current Affairs
-
UPSC LAW
Explore
Join Us
Explore
Contact Us
Explore









Ambarish Gupta
· commented
· 1 Months ago
Vijay Sharma
· commented
· 1 Months ago
Knowledge Expert
· commented
· 1 Months ago
Detailed explanation-
pipe A can fill the tank in 1 hr. = 1/60 part
pipe B can fill the tank in 1 hr. = 1/40 part
Pipe A and B can fill the tank in 1 hr.= 1/24
Let time required to fill the tank is = T hour
According to question,
pipe B can fill the tank in 1 hr. = 1/40 part
pipe B can fill the tank in T/2 hr. = 1/40* T/2= T/80
Pipe A and B can fill the tank in 1 hr.= 1/24
Pipe A and B can fill the tank in T/2 hr.= 1/24*T/48= T/48
T/80+T/48= 1 (Both are filled the tank completely)
T(3+5)/240=1
T= 240/8
T= 30 hr.
I hope you got it.
Keep learning with us!
Best wishes
Team Toprankers