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· 1 Months ago

Sanket sigh's comment is righ.!!!!

Question:
The area of the base of a cuboidal box is 21 sq. cm and the area of the faces is 30 sq. cm. The numerical value of each of the dimensions of the box is an integer greater  than 1. Then the volume of the cuboidal box (in cu. cm) is –
Options:
A) 120
B) 105
C) 210
D) 630
Solution:
Ans: (c) Area of base 21 sq. cm

             Area of faces = 30 sq. cm

                So, length = HCF of (area of base & area of faces) 

                                = 3 cm

So, volume of cuboidal box = \(\cfrac{21 × 30}{3}\)

= 210 cm3  


Alternate solution:

Knowledge Expert

· commented

· 1 Months ago

Dear student,
We have inserted an alternate solution. Hope it helps.
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