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Vijay Sharma

· started a discussion

· 1 Months ago

@knowledge expert please explain how minimum value is coming 2 in second last step

Question:

The minimum value of x2 + \(\cfrac{1}{x^2+1}-8\) is:

Options:
A) –7
B) 0
C) –9
D) Can’t be determined 
Solution:
Ans: (a) 


Thus, minimum value = 2 – 9 = –7

Arun

· commented

· 1 Months ago

The minimum value of a²+(1/a²) is 2. This is something that needs to be byhearted. Here a = (x²+1)

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