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TRINA DAS

· started a discussion

· 1 Months ago

Pay attention (Question:366553.0)

At least print the questions correctly.

Question:

If  x2-3x+1=0   , x+1x=3   then what is the value of \(x^3+\frac{1}{x^3}\) ? 

Options:
A)

     3

B)

     7

C)

     11

D)

     18

Solution:

  x2-3x+1=0   

Dividing equation by x

x+1x=3   

Cubing both sides,

x3+1x3=33-3*3=18   

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