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Parmod

· started a discussion

· 1 Months ago

Parmod Duhan (Question:248636.0)

Height 2 cm maan lo to rectangle Ka area hua 12cm sq. ab 12cm hi baki portion Ka area hoga kyonki area half De rakha h or ye area 12cm sq. 2 congurent triangle Ka area h isliye 1 Ka hua 6cm sq. ab height same h to 1/2×b×2=6 to base aya 6 . Dono tring. Ka base 6 6 ho gya or rectangle Ka base b 6 h to 6/18 =1/3

Question:
ABCD is a trapezium in which AB is parallel to DC, AD = BC, AB = 6 cm, AB = EF and DF = EC. If two lines AF and BE are drawn in such a way that area of ABEF is half of ABCD. Find CE/CD.
Options:
A) \(\cfrac{1}{2}\)
B) \(\cfrac{1}{3}\)
C) \(\cfrac{1}{4}\)
D) \(\cfrac{1}{6}\)
Solution:

Ans: (b)


Shashank Shah

· commented

· 1 Months ago

Instead they just missed one more multiplication with half

Shashank Shah

· commented

· 1 Months ago

But why should we assume height 2 cm?
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