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satish bhakher

· started a discussion

· 1 Months ago

how angle QPS 80

Question:

In the given figure, PQR and PST are tangents to the circle whose centre is ‘O’ touching the circle at Q and S respectively.    RQA = 60º and    AST = 70º. Find the value of  QPS2   .

  

Options:
A)

55º

B)

80º

C)

40º

D)

30º

Solution:

Ans: (c)

  

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given naswer is correct
In the solution
angle QPS = 360 - ( angle QAS + angle AQP + angle ASP )
= 360 - ( 50 + 120 + 110)
= 80
And follow the solution

Best wishes
Team TR

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