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KAPA NAGA SANDEEP KUMAR

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· 1 Months ago

P,Q are centers then why to use formula

Question:
In the adjoining figure, ACB is a right angled triangle. CD is the altitude. Circles are inscribed within the triangles ACD, BCD. P and Q are the centres of the circles. The distance PQ is (approx) :  

Options:
A) 5
B) \(\sqrt[]{50}\)
C) 7
D) 8
Solution:
Ans: (b)


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