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priyanka

· started a discussion

· 1 Months ago

ouestion ID NO 223895 (Question: 223895.0 )

solution of question no 61 in ouestion ID NO 223895 is not apperared. pls provide me proper solution with image by mail and other source.

priyanka
mail id: priyankagoswamigiri7@gmail.com

Question:
In a triangle DEF, points A, B and C are taken on DE, DF and EF respectively such that EC = AC and CF = BC. If \(\angle \)D = 40° then, \(\angle \)ACB = ?
Options:
A) 120
B) 60
C) 100
D) 90
Solution:
Ans: (c)

Let ∠AEC = ∠EAC = α and ∠CBF = ∠CFB = β.

We know that α + β = 180° − ∠D = 140°.

∠ACB = 180° − (∠ECA + ∠BCF)

= 180° − (180° − 2α + 180° − 2β)

= 100°.

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
We fixed the solution.
Keep learning with us!!
All the Best,
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