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Pranay SB

· started a discussion

· 1 Months ago

Other way: (Question: 259924.0 )

When it is mentioned alternatively:
Step1: subtract 'filling work' from the total work
let the total work be '1'
1-1/4=3/4
Step2: In two hours 1/12 work is finished. In how many hours 3/4 work will be finished?--> 18 hrs
Step3: What is left-> 1/4 work, which will take one more hour
total hours=18+1=19

Question:

Pipe P can fill tank in 4 hrs and pipe Q can empty it in 6 hrs. If they are opened on alternate hours and pipe P is opened first then in how many hours, the tank shall be fill?

Options:
A)

12 hours

B)

1623    hours

C)

19 hours

D)

20 hours

Solution:

Ans: (c)

  

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