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Aswathy surya

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· 1 Months ago

Correct answer is Correction for sag = (sq.root of W x l) /(24 x (sq.root of Pm)

Question:

When a tape of length (L) and weight (w) N/m is stretched at its ends with a pull (P) N, then the

correction for sag required is:

Options:
A)

wL24P    

B)

w2L224P2    

C)

w3L324P3    

D)

w4L424P4    

Solution:

Ans: (b)

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