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Sanjay Bajpai

· started a discussion

· 1 Months ago

not suff' (Question: 195903.0 )

any other solution of it?

Question:

If A cos2 \(\theta\)+ B sin2\(\theta\) =  \(\cfrac{sin^2 \ \theta \ (sec^2\theta \ + 1 )}{sec^2 \ \theta- 1}\)     then cot\(\theta\) = ?

Options:
A) \(\sqrt{\cfrac{B - 2}{2 - A}}\)
B) \(\sqrt{\cfrac{B - 1}{2 - A}}\)
C) \(\sqrt{\cfrac{B - 1}{A - 2}}\)
D) \(\sqrt{\cfrac{2 - B}{2 - A}}\)
Solution:
Ans: (b) 


ACos2θ + BSin2θ = Sin2θ + 2Cos2θ

BSin2 θ – Sin2 θ = 2 Cos2 θ – ACos2 θ

Sin2 θ (B - 1) = Cos2 θ (2 - A)

\(\cfrac{B -1}{2-A} = \cfrac{Cos^2θ}{Sin^2θ}\)

\(\sqrt{\cfrac{B-1}{2-A}}\) = Cotθ

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Here known equation is only one, thus we have to simplify the given equation then minimize form give the value, by applying trigonometric formula. So please read carefully and try again.

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