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ankita

· started a discussion

· 1 Months ago

nice (Question: 252315.0 )

good one

Question:
Let 0 < y < 1, then the correct inequality is — 
Options:
A) y < \(\sqrt{y}\) < y2
B) \(\sqrt{y}\) < y < y2
C) y2 < y < \(\sqrt{y}\)
D) \(\sqrt{y}\) < y2 < y
Solution:
Ans: (c)


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